# 1480. Running Sum of 1d Array

# Problem

Given an array `nums`

. We define a running sum of an array as `runningSum[i] = sum(nums[0]…nums[i])`

.

Return the running sum of `nums`

.

**Example 1:**

**Input:** nums = [1,2,3,4] **Output:** [1,3,6,10] **Explanation:** Running sum is obtained as follows: [1, 1+2, 1+2+3, 1+2+3+4].

**Example 2:**

**Input:** nums = [1,1,1,1,1] **Output:** [1,2,3,4,5] **Explanation:** Running sum is obtained as follows: [1, 1+1, 1+1+1, 1+1+1+1, 1+1+1+1+1].

**Example 3:**

**Input:** nums = [3,1,2,10,1] **Output:** [3,4,6,16,17]

**Constraints:**

`1 <= nums.length <= 1000`

`-10^6 <= nums[i] <= 10^6`

# Solution

```
class Solution(object):
def runningSum(self, nums):
"""
:type nums: List[int]
:rtype: List[int]
"""
result = [nums[0]]
for i in nums[1:]:
to_append = i + result[-1]
result.append(to_append)
return result
```